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6x^2+4=1354
We move all terms to the left:
6x^2+4-(1354)=0
We add all the numbers together, and all the variables
6x^2-1350=0
a = 6; b = 0; c = -1350;
Δ = b2-4ac
Δ = 02-4·6·(-1350)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*6}=\frac{-180}{12} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*6}=\frac{180}{12} =15 $
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